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Oct 18, 2019 at 15:43 history edited fuz CC BY-SA 4.0
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Oct 18, 2019 at 15:12 history edited fuz CC BY-SA 4.0
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Oct 18, 2019 at 13:05 history edited fuz CC BY-SA 4.0
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Oct 8, 2019 at 14:07 vote accept fuz
Jul 22, 2018 at 11:35 comment added MotiNK Well $S$ is defined by the above procedure. Weighting appropriately within $W$ to achieve $S$ seems very manageable. But weighting with respect to vertices in $V_k$ outside of $W$ (which are of course the majority) is the more difficult part. For example, there may be a node which has a very small number of paths to it, thus the chances of it being included in $W$ are lower than for other nodes. Is this corrected for by the weighting when it DOES make it into $W$?
Jul 22, 2018 at 10:43 comment added fuz @MotiN Do you mean $S$ by set of vertices chosen by the bootstrap sampling procedure?
Jul 22, 2018 at 10:19 comment added MotiNK I don't think that $\sum_{v \in W} b(v)^{-1} = 1$ (of course you can reweight). And what happens with vertices not appearing in $W$? The result of your random walks will of course not include a lot of those; I think you really must do a proper calculation to include the probability of a node appearing in $W$ times the chance of it being chosen by the bootstrap sampling procedure. That first probability seems very difficult to me to calculate directly.
Jul 22, 2018 at 10:08 comment added fuz @MotiN it is $v_i\in V_i$ for all $i$. I have used the same bias values as in your answer, except that I don't lose a factor of $3$ because I am not constrained to actual probabilities.
Jul 22, 2018 at 8:21 comment added MotiNK As well, I'd really suggest you do a calculation of the probability of selecting a vertex. This is really the only way to know if your algorithm is correct, rather than a gut feeling about it.
Jul 22, 2018 at 7:27 comment added MotiNK Can you add subscripts to the $C(\dot)$ functions to reflect the $i$ of $V_i$ they are for? it will make things clearer, thank you.
Jul 19, 2018 at 13:22 history edited fuz CC BY-SA 4.0
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Jul 19, 2018 at 12:30 history edited fuz CC BY-SA 4.0
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Jul 19, 2018 at 12:13 history answered fuz CC BY-SA 4.0