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In the case of a single endogenous variable and a single instrumental variable, the IV estimator is given by

$b_{IV} = \frac{cov(z,y)}{cov(z,y)}$$b_{IV} = \frac{cov(z,y)}{cov(z,x)}$

It is often mentioned that "the instrument should not affect the dependent variable directly, but only through the endogenous variable". But if the instrument should not affect the dependent variable directly,

$cov(z,y) = 0$

would hold, making

$b_{IV} = 0$.

So what is happening?

In the case of a single endogenous variable and a single instrumental variable, the IV estimator is given by

$b_{IV} = \frac{cov(z,y)}{cov(z,y)}$

It is often mentioned that "the instrument should not affect the dependent variable directly, but only through the endogenous variable". But if the instrument should not affect the dependent variable directly,

$cov(z,y) = 0$

would hold, making

$b_{IV} = 0$.

So what is happening?

In the case of a single endogenous variable and a single instrumental variable, the IV estimator is given by

$b_{IV} = \frac{cov(z,y)}{cov(z,x)}$

It is often mentioned that "the instrument should not affect the dependent variable directly, but only through the endogenous variable". But if the instrument should not affect the dependent variable directly,

$cov(z,y) = 0$

would hold, making

$b_{IV} = 0$.

So what is happening?

Source Link
Snoopy
  • 533
  • 1
  • 5
  • 16

Correlation between the dependent variable and the instrument

In the case of a single endogenous variable and a single instrumental variable, the IV estimator is given by

$b_{IV} = \frac{cov(z,y)}{cov(z,y)}$

It is often mentioned that "the instrument should not affect the dependent variable directly, but only through the endogenous variable". But if the instrument should not affect the dependent variable directly,

$cov(z,y) = 0$

would hold, making

$b_{IV} = 0$.

So what is happening?