Skip to main content
12 events
when toggle format what by license comment
Oct 22, 2018 at 13:15 vote accept J.M. Molina
Oct 19, 2018 at 15:05 comment added mdewey I think asking this question on R-help might be productive.
Oct 19, 2018 at 15:04 comment added J.M. Molina @a_statistician The package's author has a book on complex survey samples on which the procedures are based on, I should check that out.
Oct 19, 2018 at 15:00 comment added J.M. Molina @St.Inkbug According to this help page in the documentation), the default seems to be 95%, but for some reason the intervals are different that those shown there for Stata.
Oct 19, 2018 at 14:56 comment added user158565 @mdewey I do not use R. But I hope I could find the theory that support svyglm. I am very disappointed by the search results.
Oct 19, 2018 at 14:51 comment added mdewey @a_statistician in fact the confidence intervals come from the margins package but that is not explicit about how it estimates them either. I think the OP has to look at the code for enlightenment.
Oct 19, 2018 at 14:39 answer added Heteroskedastic Jim timeline score: 6
Oct 19, 2018 at 14:28 comment added user158565 I googled the information about svyglm. Its manual does not say what methods are used. So it just likes black box. I will not use it before I get the statistical theory behind the black box.
Oct 19, 2018 at 5:28 comment added St. Inkbug Are you sure that the reported confidence intervals are 95%?
Oct 18, 2018 at 22:02 comment added Heteroskedastic Jim The confidence intervals are not symmetric about the AME. When this is the case, this result is possible. The CI is not simply $AME \pm c \times SE$. So they are arrived at differently. The p-values are based on the Wald z-statistic, the CI are not Wald CI. Different assumptions, different results. This is assuming the package is not making a programming error.
Oct 18, 2018 at 21:50 review First posts
Oct 19, 2018 at 0:26
Oct 18, 2018 at 21:46 history asked J.M. Molina CC BY-SA 4.0