What is the Standard Error of the Lognormal distribution? I am particularly interested in comparing two probabilities from the distribution. I have the two proportions based on experiments, in general these proportions follow a lognormal fit.

The standard error of differences from a normal distribution is straightforward (I've seen one other version of this which I think can see on wikipedia):

$SE = \sqrt{\frac{p (1-p)}{n} + \frac{q (1-q)}{m}}$

where $p, q$ are probabilities and $n, m$ sample sizes, expected to be from a normally distributed sample.

How would this be extended to the lognormal?

What is the Standard Error of the Lognormal distribution? I am particularly interested in comparing two probabilities from the distribution. I have the two proportions based on experiments, in general these proportions follow a lognormal fit.

The standard error of differences from a normal distribution is straightforward (I've seen one other version of this which I think can see on wikipedia):

$SE = \sqrt{\frac{p (1-p)}{n} + \frac{q (1-q)}{m}}$

where $p, q$ are probabilities and $n, m$ sample sizes, expected to be from a normally distributed sample.

How would this be extended to the lognormal?

Edit:

The basic idea is to learn if the difference between two probabilities would be significant or not. I don't think I'm expressing my question correctly as I'm not a strict statistician.

What is the Standard Error of the Lognormal distribution? I am particularly interested in comparing two probabilities from the distribution. I have the two proportions based on experiments, in general these proportions follow a lognormal fit.

The standard error of differences from a normal distribution is straightforward (I've seen one other version of this which I think can see on wikipedia):

SE = sqrt(p (1-p) / n + q (1-q) / m)

where p,q are probabilities and n,m sample sizes, expected to be from a normally distributed sample.

How would this be extended to the lognormal?

What is the Standard Error of the Lognormal distribution? I am particularly interested in comparing two probabilities from the distribution. I have the two proportions based on experiments, in general these proportions follow a lognormal fit.

The standard error of differences from a normal distribution is straightforward (I've seen one other version of this which I think can see on wikipedia):

$SE = \sqrt{\frac{p (1-p)}{n} + \frac{q (1-q)}{m}}$

where $p, q$ are probabilities and $n, m$ sample sizes, expected to be from a normally distributed sample.

How would this be extended to the lognormal?