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Feb 5, 2019 at 21:00 history tweeted twitter.com/StackStats/status/1092890614767763457
Feb 5, 2019 at 16:30 comment added Simon Boge Brant It seems to me that they do not justify the comparison between these models via the AIC, or discuss some method of making the AIC scores comparible (I do not know if this is possible), so that part of the paper certainly looks strange to me. The conclusions may be valid for all I know, but it seems like the authors of that paper, and the reviewers (if there were any) have insufficient knowledge of quite basic statistics.
Feb 5, 2019 at 16:23 comment added Simon Boge Brant AIC is a comparison based on the likelihood. The "trick" in Cox regression is to write out the likelihood in terms of a hazard of the form $\alpha(t\vert x) = \alpha_0(t)e^{\eta(x)},$ so that $\alpha_0(t)$ can be factored out. Due to this, what you end up with maximising is not an actual likelihood, but a partial likelihood, and therefore the comparison between the Cox partial likelihood and the likelihood of a parametric model does not make sense, they are not on the same scale.
Feb 4, 2019 at 21:03 comment added Leevo Thank you for the suggestions, I never heard of these measures. This raises two more questions: 1) What are the reasons of incompatibility of AICs? 2) Those papers that compare parametric and semiparametric models using AIC, BIC, etc... are they junk science?
Feb 4, 2019 at 18:39 comment added Simon Boge Brant Due to the way the AIC-criterion is defined, parametric and semi-parametric survival models are not comparable via AIC. I think the (easiest) sensible way of comparing parametric and semi-parametric survival models would be through some kind of measure based on predictions such as Brier score, AUC, etc. If you like to read some mathematics, you could also read link.springer.com/article/10.1007%2Fs10985-018-9450-7, where the authors develop an information criterion for these kinds of comparisons.
Feb 4, 2019 at 18:02 history asked Leevo CC BY-SA 4.0