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May 22, 2023 at 7:00 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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May 13, 2022 at 2:52 comment added Glen_b Given that $t^2 = F$, it's not clear why "uses an F-test" would be dispositive of itself.. I think a deeper argument would be needed here.
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Jun 30, 2021 at 8:36 answer added ChrisD timeline score: 1
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Feb 15, 2019 at 10:43 answer added Izy timeline score: 1
Feb 15, 2019 at 8:30 comment added user2974951 ANOVA uses an F-test, so the two are not compatible.
Feb 15, 2019 at 8:20 review First posts
Feb 15, 2019 at 8:50
Feb 15, 2019 at 8:19 history asked YBA CC BY-SA 4.0