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Apr 19, 2019 at 3:24 vote accept CommunityBot
Apr 15, 2019 at 22:40 answer added StubbornAtom timeline score: 3
Apr 14, 2019 at 22:54 history edited user242554 CC BY-SA 4.0
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Apr 14, 2019 at 22:40 comment added StubbornAtom If the score $U(\mathbf X)=\frac{\partial}{\partial\theta}\ln f(X_1,\ldots,X_n\mid \theta)$ is such that $U\stackrel{a}\sim N(0,I(\theta))$, then definitely a pivot is $\frac{U}{\sqrt{I(\theta)}}\sim N(0,1)$.
Apr 14, 2019 at 22:15 history edited user242554 CC BY-SA 4.0
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Apr 14, 2019 at 22:10 history asked user242554 CC BY-SA 4.0