Timeline for Confused about conditional counterparts to traditional probability laws

5 events

when toggle format	what		by	license	comment
Dec 30, 2019 at 17:04	vote	accept	Noah Stebbins
May 23, 2019 at 21:40	history	edited	kjetil b halvorsen♦	CC BY-SA 4.0	added 52 characters in body
May 12, 2019 at 15:42	history	edited	kjetil b halvorsen♦	CC BY-SA 4.0	added 915 characters in body
May 7, 2019 at 22:45	comment	added	Noah Stebbins		Thank you for the response! The formula above for $Q(\cdot) = P(\cdot\|\theta)$ makes sense for $Q(x,y)$ and $Q(y)$ as those terms would translate to $P(x,y\|\theta)$ and $P(y\|\theta)$ respectively, but what about for $Q(x\|y)$? Wouldn't that term translate to $P(x\|y\|\theta)$? Why does $P(x\|y\|\theta) = P(x\|y, \theta)$?
May 7, 2019 at 21:13	history	answered	kjetil b halvorsen♦	CC BY-SA 4.0