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Apr 13, 2017 at 12:44 history edited CommunityBot
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Oct 22, 2012 at 5:35 comment added user1172558 Yes. x1 and x2 are factors, but not pre. I posted the str(data) above.
Oct 22, 2012 at 5:30 comment added mnel Are you sure that x1 and x2 are coded as factors? Should pre be a factor?
Oct 22, 2012 at 5:29 review First posts
Oct 22, 2012 at 5:52
Oct 22, 2012 at 5:27 comment added user1172558 I don't know why, but I can't get this result. Even using drop1() options(contrasts=c("contr.sum","contr.poly")) m2 <- lm(y ~ pre + x1*x2, data) summary(m2) anova(m2) drop1(m2, .~., test='F') # Type III SS The only result which is still correct is the one for 'pre'.
Oct 22, 2012 at 5:21 vote accept user1172558
Oct 22, 2012 at 5:22
Oct 22, 2012 at 5:15 history edited mnel CC BY-SA 3.0
added 63 characters in body
Oct 22, 2012 at 5:10 history answered mnel CC BY-SA 3.0