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Jun 4, 2019 at 16:10 comment added msloryg Thank you! If I am getting you right, this is exactly the formula to estimate $\sigma^2$ that I have written down (which is the MSE). So you say that is okay that the is $BIC = n + \log(n) \cdot d$? That seems weird to me
Jun 4, 2019 at 14:00 history answered David CC BY-SA 4.0