Timeline for Deriving Bellman's Equation in Reinforcement Learning
Current License: CC BY-SA 4.0
13 events
when toggle format | what | by | license | comment | |
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S Jan 18 at 0:57 | history | suggested | bilibraker | CC BY-SA 4.0 |
deleting redundant line, changing 2 "\mid" to "|" for consistency
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Jan 18 at 0:46 | review | Suggested edits | |||
S Jan 18 at 0:57 | |||||
Jan 18 at 0:43 | comment | added | bilibraker | superb answer, cleared up a lot of things! | |
Jul 13, 2023 at 20:39 | review | Suggested edits | |||
Jul 13, 2023 at 20:45 | |||||
Jul 13, 2023 at 20:28 | history | edited | Finncent Price | CC BY-SA 4.0 |
the edits that were made 14 hours ago are not mathematically correct, the short proof has been changed to be correct
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S Jul 13, 2023 at 6:39 | history | edited | utobi | CC BY-SA 4.0 |
Short helper proof for a part of answer
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S Jul 13, 2023 at 6:39 | history | suggested | Kanishk | CC BY-SA 4.0 |
Short helper proof for a part of answer
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Jul 13, 2023 at 6:00 | review | Suggested edits | |||
S Jul 13, 2023 at 6:39 | |||||
Dec 17, 2020 at 22:42 | comment | added | Fabian Werner | but only on the variables $S_{t-1}, A_{t-1}, R_{t-1}$... ). So if you say that then you have a different definition of 'markovian' than everybody else I guess... | |
Dec 17, 2020 at 22:41 | comment | added | Fabian Werner | Two comments on this interesting answer: 1. Even if the reward is either 0 or 1, the values that $G_t$ may take can nevertheless be bigger so we need an integral instead of a sum over $\gamma$. 2. What exactly is $p(g|...)$ supposed to be? Let's start simple: what is $p(g)$ supposed to be? It is the density of $G_{t+1}$, right? Why does this random variable even have a density? Even if it had a density, why exactly does it not depend on $s$ in the sense that you wrote down? This is not the Markov property (Markov says that the single variables $S_t, A_t, R_t$ do not depend on the whole past... | |
Dec 8, 2020 at 20:57 | vote | accept | Amelio Vazquez-Reina | ||
Jun 27, 2019 at 15:04 | history | edited | Finncent Price | CC BY-SA 4.0 |
Clarified a point about the Markovian property
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Jun 20, 2019 at 15:51 | history | answered | Finncent Price | CC BY-SA 4.0 |