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I made a mistake. I wrote Corr but the correct is Cov

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edited Jul 3, 2019 at 12:06

Why $Corr$Cov(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$?

I'm trying to proof some results in Multiple Linear Regression.
In matrix notation, why $Corr(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$$Cov(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$?

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asked Jul 3, 2019 at 11:50

igorkf

Why $Corr(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$

I'm trying to proof some results in Multiple Linear Regression.
In matrix notation, why $Corr(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$?

correlation multiple-regression

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Why $Corr$Cov(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$?

Why $Corr(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$

Why $Cov(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$?

Why $Corr(\pmb{y}, \pmb{\hat{y}}) = \pmb{y}^T \pmb{\hat{y}}$