Suppose I have the joint distribution:
\begin{align} p(\mathbf{x}) = p(x_1, ... , x_n) \end{align}
The maximum a posteriori (MAP) solution is given by:
\begin{align} \mathbf{x}_{MAP} = \arg \min p(\mathbf{x}) \end{align}\begin{align} \mathbf{x}_{MAP} = \arg \max p(\mathbf{x}) \end{align}
Intuitively I believe that finding the maximums of each marginal should not always correspond to $\mathbf{x}_{MAP}$. That is,
\begin{align} \mathbf{x}_{MAP_1} \neq \max_{x_1}(p(x_1))\\ \mathbf{x}_{MAP_2} \neq \max_{x_2}(p(x_2)) \\ \vdots \\ \mathbf{x}_{MAP_n} \neq \max_{x_n}(p(x_n)) \end{align}
I believe this should be the case, HOWEVER I can't convince myself fully. Every joint distribution I imagine, tends to satisfy this trivially (e.g. the mode of a multi-variate Gaussian, can be found by considering the mode for each of the marginals).
- Is there/are there counter-examples to prove this point?
- Or perhaps is my intuition wrong? That is, the mode of the marginals always corresponds to the MAP mode.
- Are there sources on the internet which explore this issue in depth (since no matter what I Google I cannot find an answer on this)?
- Are there any conditions to declare when this is / isn't true?