- Making some assumptions about the population size (namely that it is large enough that a binomial model is appropriate), the prevalence of a disease in a population at a particular time can be obtained by
samplingsimple random sampling of people and finding who is sick. That is a binomial random variable and the Wald confidence interval for a proportion $p$ is
$$ p \pm 1.96\dfrac{\sqrt{p(1-p)}}{\sqrt{n}}$$
The variance portion is bounded above by 0.5, so we can make the simplifying assumption that the width of the confidence interval is $\sim 2/\sqrt{n}$. So, the answer to this part is that the confidence interval for $p$ decreases like $1/\sqrt{n}$. Quadruple your sample, halve your interval. Now, this was based on using a Wald interval, which is known to be problematic when $p$ is near 0 or 1, but the spirit remains the same for other intervals.
- You need to look at metrics like specificity and sensitivity.
Sensitivity is the probability that a diseased person will be identified as diseased (i.e. tests positive). Specificity is the probability that a person without the disease is identified as not having the disease (i.e. tests negative). There are lots of other metrics for diagnostic tests found here which should answer your question.
- I guess this is still up in the air. There are several attempts to model the infection over time. SIR models and their variants can make a simplifying assumption that the population is closed (i.e. S(t) + I(t) + R(t) = 1) and then I(t) can be interpreted as the prevalence. This isn't a very good assumption IMO because clearly the population is not closed (people die from the disease). As for modelling the diagnostic properties of a test, those are also a function of the prevalence. From Bayes rule
$$ p(T+ \vert D+) = \dfrac{P(D+\vert T+)p(T+)}{p(D+)}$$
Here, $P(D+)$ is the prevalence of the disease, so as this changes then the sensitivity should change as well.