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Nov 12, 2020 at 5:25 vote accept nOp
May 31, 2020 at 13:40 comment added whuber Since all eigenvalues of $ACA^\top$ are equal, automatically $Ab$ is an eigenvector with the largest eigenvalue.
May 30, 2020 at 21:03 comment added nOp Thanks! Can anything be said regarding the part that we want $\mathbf{A}b$ to be in the direction of the biggest eigenvalue of $\mathbf{A}\mathbf{C}\mathbf{A}^T$? (for example for the case $2\times 2$ matrices)
May 30, 2020 at 19:29 vote accept nOp
Nov 12, 2020 at 5:25
May 30, 2020 at 12:22 history edited whuber CC BY-SA 4.0
deleted 15 characters in body
May 30, 2020 at 11:59 history answered whuber CC BY-SA 4.0