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carlo
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I guess that if you perform a crisp linear SVM classifier between two groups, one of it being your data and the other being the null vector, either the algorithm will fail because 0 is in the convex hull of those points (groups not linearly separable), or a solution will be found, where one of the SVSVs will clearly be 0, and the others stay onother k vectors define the surfacek-face of the hull nearest to the origin.

I guess that if you perform a crisp linear SVM classifier between two groups, one of it being your data and the other being the null vector, either the algorithm will fail because 0 is in the convex hull of those points (groups not linearly separable), or a solution will be found, where one of the SV will clearly be 0, and the others stay on the surface of the hull nearest to the origin.

I guess that if you perform a crisp linear SVM classifier between two groups, one of it being your data and the other being the null vector, either the algorithm will fail because 0 is in the convex hull of those points (groups not linearly separable), or a solution will be found, where one of the SVs will clearly be 0, and the other k vectors define the k-face of the hull nearest to the origin.

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carlo
  • 5.1k
  • 1
  • 14
  • 31

I guess that if you perform a crisp linear SVM classifier between two groups, one of it being your data and the other being the null vector, either the algorithm will fail because 0 is in the convex hull of those points (groups not linearly separable), or a solution will be found, where one of the SV will clearly be 0, and the others stay on the surface of the hull nearest to the origin.