Timeline for Expected rolls to roll every number on a dice an odd number of times
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 23, 2020 at 6:41 | vote | accept | Peter Prescott | ||
| Jun 22, 2020 at 22:59 | history | became hot network question | |||
| Jun 22, 2020 at 21:24 | comment | added | whuber♦ | I don't need to--Stephan has done a beautiful job of it already :-). | |
| Jun 22, 2020 at 21:00 | history | tweeted | twitter.com/StackStats/status/1275171733893517320 | ||
| Jun 22, 2020 at 20:49 | answer | added | Stephan Kolassa | timeline score: 21 | |
| Jun 22, 2020 at 19:47 | comment | added | Peter Prescott | Well go on then @whuber :) | |
| Jun 22, 2020 at 17:25 | comment | added | whuber♦ | This is a beautifully symmetric Markov chain on the discrete $6$-cube $\{0,1\}^6$ and as such it's straightforward to derive the entire distribution, not just the expectation, and to do so from any position. With the distribution in hand you can then immediately derive the distribution for any number of players, because it's just the minimum of their rolls to reach the goal. For an unfair die the same calculations apply but the symmetry is broken. | |
| Jun 22, 2020 at 16:09 | answer | added | Peter Prescott | timeline score: 11 | |
| Jun 22, 2020 at 15:06 | review | First posts | |||
| Jun 22, 2020 at 15:19 | |||||
| Jun 22, 2020 at 14:56 | history | asked | Peter Prescott | CC BY-SA 4.0 |