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Jan 23, 2013 at 20:38 vote accept learner
Jan 18, 2013 at 21:05 comment added learner So, if I understand you, one possible procedure would be to calculate either the geometric mean or determinant of a correlation matrix for any subset of the p number of variables (excluding Z) in my dataset. Is that correct?
Jan 18, 2013 at 18:06 comment added ttnphns Geometric mean has also another obvious sense: the product is really big when its factors are big jointly. Determinant is the "volume" of the correlation matrix, - the product of its eigenvalues. When correlations are small, det is high; when either they are big or there is collinearities, det is close to 0.
Jan 18, 2013 at 16:32 comment added learner @ttnphns, I have heard that the difference between the arithmetic mean and the geometric mean is that the geometric mean reduces the impact of unusually high and low values in the quantities examined (correlations, here). What insight is the determinant of the correlation matrix providing?
Jan 18, 2013 at 9:45 comment added ttnphns @learner, if you want summarize the strengths of intercorrelations among p variables in a single number you could compute, for example, (1) average abs. correlation or (2) geometric mean abs. correlation, or (3) determinant of abs(corr. matrix). These three are very different ways to conceptualize p-variate association by a single value.
Jan 18, 2013 at 2:02 answer added rolando2 timeline score: 4
Jan 17, 2013 at 22:44 history edited user88 CC BY-SA 3.0
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Jan 17, 2013 at 21:01 comment added learner If I read that correctly, the coefficient of determination gives an idea about how several measurements correlate together with a single variable (Z in this case). What if I want to get a feel for the relationship between these other variables, without reference to Z?
Jan 17, 2013 at 19:30 comment added Stephan Kolassa You may be looking for the coefficient of determination of a regression of $z$ on $x_1, \dots, x_5$: en.wikipedia.org/wiki/Coefficient_of_determination But beware, interpreting it can be misleading.
Jan 17, 2013 at 18:49 review First posts
Jan 17, 2013 at 19:20
Jan 17, 2013 at 18:30 history asked learner CC BY-SA 3.0