Timeline for Proving that a function is not a kernel function
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 12, 2020 at 19:01 | vote | accept | christopher | ||
| Sep 12, 2020 at 17:39 | answer | added | carlo | timeline score: 2 | |
| Sep 12, 2020 at 13:51 | comment | added | christopher | @carlo yes! could you show me how? | |
| Sep 12, 2020 at 12:17 | comment | added | carlo | it's not positive definite, if I didn't any mistake in the computations by mind. is it this what you are asking? | |
| Sep 12, 2020 at 12:05 | comment | added | christopher | yes it can be any vector. @carlo | |
| Sep 12, 2020 at 12:03 | review | Close votes | |||
| Sep 12, 2020 at 23:43 | |||||
| Sep 12, 2020 at 12:02 | comment | added | carlo | wait... $x'$ can be any vector? I thought it was $x$ translated | |
| Sep 12, 2020 at 11:56 | comment | added | christopher | @carlo even if we consider other entity to be 0? | |
| Sep 12, 2020 at 11:46 | comment | added | carlo | a function of two arguments can't be defined by using the same argument twice | |
| Sep 12, 2020 at 11:23 | history | edited | christopher | CC BY-SA 4.0 |
added 171 characters in body; edited title
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| Sep 12, 2020 at 11:21 | comment | added | christopher | No its not a typo! yes agreed it does depends on both $x$ and $x'$ but how to formally show that!. Yeah i am updating the title thanks | |
| Sep 12, 2020 at 11:19 | comment | added | air | Is there a typo in the title? The kernel function depends on both $x,x'$. Also I think it's always nice when the main question includes all details required to answer (instead of "frontloading" some details to the title). | |
| Sep 12, 2020 at 11:03 | history | asked | christopher | CC BY-SA 4.0 |