Consider the situation where one can distinguish between two different event $A$ and $B$, where the first event $A$ is characterized by a random variable $x_{A}\sim P_{A}\left(x_{A} \right)$ and the second event $B$ is characterized by a second random variable $x_{B}\sim P_{B}\left(x_{B}|x_{A} \right)$, respectively ($x_{A}, x_{B}\in \mathbb{R}$). Note that while the random variable $x_{A}$ of the first event $A$ is distributed independently of the outcome of event $B$, the outcome of event $B$ is generally conditioned on the outcome of event $A$. Therefore, one can also write $(x_{A}, x_{B})\sim P_{AB}\left(x_{A},x_{B} \right)$, where by the rule of conditional probabilities \begin{equation} P_{AB}\left(x_{A},x_{B} \right) = P_{A}\left(x_{A} \right) P_{B}\left(x_{B}|x_{A} \right). \end{equation}

Suppose we are then interested in the average of some function $f: (x_{A}, x_{B}) \rightarrow \mathbb{R}$. Meaning, we want to compute \begin{equation} \langle f \rangle = \int\int P_{A}(x_{A}) P_{B}(x_{B}|x_{A}) f(x_{A}, x_{B})dx_{A}dx_{B}. \end{equation}

When modelling these two events we ignore their dependence and describe them as two independent events governed by probability densities $P_{A}(x_{A})$ and $P_{B}^{\rm eff}(x_{B}) = \int P_{A}(x_{A})P_{B}(x_{B}|x_{A})dx_{A}$. Then \begin{equation} \tilde{\langle f \rangle} = \int\int P_{A}(x_{A}) P_{B}^{\rm eff}(x_{B}) f(x_{A}, x_{B}) dx_{A}dx_{B} = \int P_{B}^{\rm eff}(x_{B}) f^{\rm eff}(x_{B}) dx_{B}, \end{equation} with $f^{\rm eff}(x_{B}) = \int P_{A}(x_{A}) f(x_{A}, x_{B}) dx_{A}$.

Making this model assumption, what is my error $E=\langle f \rangle - \tilde{\langle f \rangle}$? Or in other words, can one detect a flawed model which ignores the dependence of two events just from computing an average quantity $\leftrightarrow$ is $E \neq 0$? What's the intuition behind this fact?

Consider the situation where one can distinguish between two different event $A$ and $B$, where the first event $A$ is characterized by a random variable $x_{A}\sim P_{A}\left(x_{A} \right)$ and the second event $B$ is characterized by a second random variable $x_{B}\sim P_{B}\left(x_{B}|x_{A} \right)$, respectively ($x_{A}, x_{B}\in \mathbb{R}$). Note that while the random variable $x_{A}$ of the first event $A$ is distributed independently of the outcome of event $B$, the outcome of event $B$ is generally conditioned on the outcome of event $A$. Therefore, one can also write $(x_{A}, x_{B})\sim P_{AB}\left(x_{A},x_{B} \right)$, where by the rule of conditional probabilities \begin{equation} P_{AB}\left(x_{A},x_{B} \right) = P_{A}\left(x_{A} \right) P_{B}\left(x_{B}|x_{A} \right). \end{equation}

Suppose we are then interested in the average of some function $f: (x_{A}, x_{B}) \rightarrow \mathbb{R}$. Meaning, we want to compute \begin{equation} \langle f \rangle = \int\int P_{A}(x_{A}) P_{B}(x_{B}|x_{A}) f(x_{A}, x_{B})dx_{A}dx_{B}. \end{equation}

When modelling these two events we ignore their dependence and describe them as two independent events governed by probability densities $P_{A}(x_{A})$ and $P_{B}^{\rm eff}(x_{B}) = \int P_{A}(x_{A})P_{B}(x_{B}|x_{A})dx_{A}$. Then \begin{equation} \tilde{\langle f \rangle} = \int\int P_{A}(x_{A}) P_{B}^{\rm eff}(x_{B}) f(x_{A}, x_{B}) dx_{A}dx_{B} = \int P_{B}^{\rm eff}(x_{B}) f^{\rm eff}(x_{B}) dx_{B}, \end{equation} with $f^{\rm eff}(x_{B}) = \int P_{A}(x_{A}) f(x_{A}, x_{B}) dx_{A}$.

Making this model assumption, what is my error $E=\langle f \rangle - \tilde{\langle f \rangle}$? Or in other words, can one detect a flawed model which ignores the dependence of two events just from computing an average quantity $\leftrightarrow$ is $E \neq 0$? There are certainly common ways to figure out whether two events are independent or not; is a computation of $E$ one of them? What's the intuition behind this fact? Intuitively it should certainly be harder to detect the dependence of events if one does not have full access to the underlying probability densities, i.e., access to the probability of individual sequences of events ...