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Mar 18, 2013 at 2:33 history edited Glen_b CC BY-SA 3.0
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Mar 18, 2013 at 0:13 history edited Glen_b CC BY-SA 3.0
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Mar 18, 2013 at 0:07 history edited Glen_b CC BY-SA 3.0
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Mar 18, 2013 at 0:05 comment added Glen_b Correct (though strictly you're leaving out some equalities at the bounds, they have probability of measure zero so teh answer won't change) - but you should probably add that question to your original post
Mar 18, 2013 at 0:03 comment added Mathlete And if I wanted to calculate $P(|X|>1)$ could I do: 1 - P(-1<X<1)?
Mar 18, 2013 at 0:01 history edited Glen_b CC BY-SA 3.0
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Mar 17, 2013 at 23:45 history answered Glen_b CC BY-SA 3.0