Timeline for Integrating with considering two indicator function
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 15, 2021 at 5:00 | vote | accept | Optimized Life | ||
| Sep 14, 2021 at 18:08 | answer | added | Fiodor1234 | timeline score: 2 | |
| Sep 14, 2021 at 15:47 | comment | added | Optimized Life | @whuber, Thanks, can you explain to me in more detail? If it is in the form of an answer, I would be very grateful. | |
| Sep 14, 2021 at 15:34 | comment | added | whuber♦ | The expectation is incorrectly expressed. The expectation is a triple integral, $$E\left[X1_{X\lt Y}1_{X\lt Z}\right] = \int_0^\infty \int_0^\infty \int_0^\infty x 1_{x\lt y} 1_{x \lt z} f_{X,Y,Z}(x,y,z)\,\mathrm{d}x\mathrm{d}y\mathrm{d}z.$$ You can easily evaluate it by assuming $X,Y,Z$ are independent. | |
| Sep 14, 2021 at 14:17 | comment | added | Optimized Life | Thanks, I actually know this, but I want to solve this directly by specifying integral intervals. | |
| Sep 14, 2021 at 13:53 | comment | added | Fiodor1234 | Notice that $\mathbb{I}_{X<Y}\mathbb{I}_{X<Z}$ is non zero if $X<min(Z,Y)$ | |
| Sep 14, 2021 at 13:09 | history | edited | Optimized Life | CC BY-SA 4.0 |
added 106 characters in body
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| Sep 14, 2021 at 12:47 | history | asked | Optimized Life | CC BY-SA 4.0 |