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Oct 13, 2022 at 8:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Sep 28, 2021 at 9:00 history tweeted twitter.com/StackStats/status/1442776128406556676
Sep 27, 2021 at 23:29 answer added Ben timeline score: 2
Sep 27, 2021 at 22:07 answer added Dilip Sarwate timeline score: 1
Sep 27, 2021 at 19:29 comment added Alec Thanks! My question has been answered completely in these comments. @periwinkle - Give me something to checkmark? :)
Sep 27, 2021 at 15:34 history edited kjetil b halvorsen
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Sep 26, 2021 at 22:51 comment added Glen_b Some books do treat $E[g(X)]= \int_x g(x) dF$ ($ = \sum_x g(x)p(x)$) as the definition of expectation, but more derive it from the ordinary definition of $E(X)$.
Sep 26, 2021 at 21:03 comment added periwinkle This result is indeed mathematically provable and not just some obvious identity. Is called the "law of the uncounscious statistician". According to Wikipedia it is called like that because "of a purported tendency to use the identity without realizing that it must be treated as the result of a rigorously proved theorem, not merely a definition". See en.wikipedia.org/wiki/Law_of_the_unconscious_statistician
S Sep 26, 2021 at 20:55 review First questions
Sep 26, 2021 at 21:24
S Sep 26, 2021 at 20:55 history asked Alec CC BY-SA 4.0