Timeline for Data analysis for "aviator" online casino game
Current License: CC BY-SA 4.0
18 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 25, 2023 at 12:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jun 24, 2023 at 5:06 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 16, 2023 at 2:05 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 13, 2022 at 14:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 9, 2022 at 18:49 | history | protected | kjetil b halvorsen♦ | ||
| Sep 4, 2022 at 17:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 30, 2022 at 3:05 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 29, 2021 at 14:15 | answer | added | Henry | timeline score: 1 | |
| Sep 29, 2021 at 14:14 | comment | added | Dots | So any ideas to analyse those numbers? Im thinking of how often big numbers (>10) come that is how far apart they usually are, and calculate probabilities after many consecutive payoffs <2. i.e. -> [1.3,1.2,1.5,1.7,1.3] -> in my dataset how probable is it that a number >2 comes | |
| Sep 29, 2021 at 14:11 | comment | added | Dots | Yes they do a trick with the coef. to make you think you win more where they remove your bet immediately from your account so if I bet 2 dollars that the coef. is 3 and the actual is 10 then I win 3xbet-bet = 3*2-2=4 | |
| Sep 29, 2021 at 13:11 | comment | added | Adrià Luz | @Henry I think I see where my confusion is coming from. I interpreted the win payout to be the difference between my guess and the actual guess, when I undershoot. For example, if I guessed 1.5 and the actual payout was 4.1 I would win 4.1-1.5=2.6. Which sounds stupid, I know. This is why on my first comment I said that there must have been something missing in the explanation. Turns out it was my fault! Obviously, if all you win is the difference between your guess and 1, then guessing the minimum possible return doesn't make any sense. | |
| Sep 29, 2021 at 13:04 | comment | added | Henry | @AdriàLuz I did not know anything about it either (I invented the tie idea, so may be wrong. But if $99\%$ of the time you would win $0.01$ while $1\%$ of the time you would lose $1$, then your expected change is $+0.01\times 0.99 - 1 \times 0.01 = -0.0001$, i.e. losing. This promotional link says "The lowest playing coefficient in Aviator is 1. It does not fall out very often, on average every 50 rounds." | |
| Sep 29, 2021 at 12:59 | comment | added | Adrià Luz | Note I'm also assuming (as per the details shared by the OP) that when you lose you only lose your bet for that round ($1). | |
| Sep 29, 2021 at 12:58 | comment | added | Adrià Luz | @Henry I'm definitely missing something (as I said I don't know anything about the game apart from what the OP shared). Just with the info shared, assuming that (1) you also lose on ties, that (2) the lowest allowed guess is 1.01, and that (3) 1.01 happens 1% of the time, guessing 1.01 every round would result in winning something 99% of the time (and this something could potentially be very large e.g. if the actual return was x1000). Based on these assumptions and my very limited knowledge I don't see why guessing 1.01 would be a losing strategy. But again, I'm sure I'm missing something! | |
| Sep 29, 2021 at 12:52 | comment | added | Henry | @AdriàLuz I see a $1.01$ near the bottom of the list. Perhaps you lose on ties, so if that happens $1\%$ of the time or more often then guessing $1.01$ would be a losing strategy | |
| Sep 29, 2021 at 12:08 | comment | added | Adrià Luz | I'm not familiar with the game, but I suspect there's something wrong or missing in your explanation. You're saying that if you undershoot you win the difference, and if you overshoot you only lose $1. If this was the case, the best strategy would be to always guess the minimum possible return, wouldn't it? | |
| S Sep 29, 2021 at 10:46 | review | First questions | |||
| Sep 29, 2021 at 10:49 | |||||
| S Sep 29, 2021 at 10:46 | history | asked | Dots | CC BY-SA 4.0 |