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Jul 20, 2022 at 7:22 history edited jfiedler CC BY-SA 4.0
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Jul 20, 2022 at 7:17 vote accept jfiedler
Jul 19, 2022 at 16:08 comment added bdeonovic to clarify @whuber's point a mixture distribution would be something like $p_Y(y) = w*p_{X_1}(y) + (1-w)*p_{X_2}(y)$ where $p_Y, p_{X_1}, p_{X_2}$ are density functions and as whuber points out if $p_{X_1}=p_{X_2}$ then $p_Y=p_{X_1}=p_{X_2}$ for any value of $w$.
Jul 19, 2022 at 15:00 history tweeted twitter.com/StackStats/status/1549408725139705857
Jul 19, 2022 at 14:40 history edited whuber CC BY-SA 4.0
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Jul 19, 2022 at 14:30 history edited whuber
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Jul 19, 2022 at 14:29 answer added whuber timeline score: 9
Jul 19, 2022 at 8:32 comment added jfiedler Thanks for clarifying the notation - I honestly did not know how to label this combination. I would like to know the answer to the mathematically formulated problem.
Jul 18, 2022 at 14:49 comment added whuber This is not a random mixture. A mixture of two identical distributions is the distribution itself, whence making a random choice of the weights will not change the distribution. This is a random linear combination or, if you like, a random convex combination of the two values. So, which question do you want answered: the one about a random mixture or the one you have written mathematically?
S Jul 18, 2022 at 13:36 review First questions
Jul 18, 2022 at 15:09
S Jul 18, 2022 at 13:36 history asked jfiedler CC BY-SA 4.0