Timeline for How do I handle expectation in this problem?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 16, 2022 at 15:43 | vote | accept | Imran Farid | ||
| Oct 16, 2022 at 15:36 | comment | added | Stratos supports the strike | @ImranFarid see my edit. Hope it's clear enough ! | |
| Oct 16, 2022 at 15:35 | history | edited | Stratos supports the strike | CC BY-SA 4.0 |
fixed my misreading of the original question
|
| Oct 16, 2022 at 12:38 | comment | added | Stratos supports the strike | Oops, my bad I misread the problem statement. But anyway yes, you got it right : you need to solve for $E[X|Y=1]$ and $E[X|Y=2]$ separately and then plug in to the expression of $E[X]$. I will edit my answer shortly | |
| Oct 16, 2022 at 11:47 | comment | added | Imran Farid | Thanks. For conditional expectation, I believe the student if staying in playground isn't restarting the process from scratch but either chooses to stay in playground or go home in the next iteration. (The original process had student with three choices: playground, mall or home) The same true for the mall. Shouldn't it be $$E[X|Y=1] = (2 + E[X|y=1] )0.4 + 0.6 $$ for playground and $$E[X|Y=2] = (3 + E[X|y=2] )0.3 + 0.7 $$ for mall? | |
| Oct 16, 2022 at 10:19 | history | answered | Stratos supports the strike | CC BY-SA 4.0 |