Timeline for Is this a nested model and can I use the likelihood ratio test?
Current License: CC BY-SA 3.0
12 events
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May 5, 2017 at 20:59 | history | edited | amoeba |
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Jul 26, 2013 at 8:00 | answer | added | tiantianchen | timeline score: 2 | |
Jun 20, 2013 at 10:27 | comment | added | Glen_b | That's a very good question to ask. You should edit to add that to your question. | |
Jun 20, 2013 at 10:26 | history | edited | tiantianchen | CC BY-SA 3.0 |
added 38 characters in body
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Jun 20, 2013 at 10:20 | comment | added | tiantianchen | I know a more standard way to obtain something similar to model2: introduce a second stratification variable-group and apply the model ($\beta$,$\beta_{group}$) to the total_data. The likelihood ratio test would be to test against H0:$\beta_{group}=0$. Is this the same as the method I described above? | |
Jun 20, 2013 at 10:19 | comment | added | Glen_b | You still need to resolve the question of what you mean by "maxlog-likelihood" earlier; I suggest making an edit to clarify both parts of your question. | |
Jun 20, 2013 at 10:17 | comment | added | tiantianchen | Yes, this is what I suppose in this method: the log-likelihoods for the subsets can be added to obtain the overall log-likelihood. I don't know whether this is valid and I need some expert to point out what's the problem with this. | |
Jun 20, 2013 at 9:40 | comment | added | Glen_b | What is 'maxlog-likelihood'? Is it the maximum of the log-likelihood, or the maximizer of it? Whichever it is, why can you sum them? Do you mean instead that the log-likelihoods for the subsets can be added to obtain the overall log-likelihood, or that the maximum value of the overall log-likelihood must always be the sum of the two maximum values obtained on the subsets? | |
Jun 20, 2013 at 9:38 | history | edited | Glen_b | CC BY-SA 3.0 |
formatting, spelling etc
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S Jun 20, 2013 at 9:27 | history | suggested | jonsca | CC BY-SA 3.0 |
Removed thanks, minor grammar
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Jun 20, 2013 at 8:51 | review | Suggested edits | |||
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Jun 20, 2013 at 8:44 | history | asked | tiantianchen | CC BY-SA 3.0 |