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User1865345
User1865345
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Question about a Why do normal equation proofequations always have at least one solution?

How can you prove that the normal equations: $(X^TX)\beta = X^TY$$(X^\top X)\beta = X^\top Y$ have one or more solutions without the assumption that X$X $ is invertible?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

Question about a normal equation proof

How can you prove that the normal equations: $(X^TX)\beta = X^TY$ have one or more solutions without the assumption that X is invertible?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

Why do normal equations always have at least one solution?

How can you prove that the normal equations: $(X^\top X)\beta = X^\top Y$ have one or more solutions without the assumption that $X $ is invertible?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

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Nick Cox
Nick Cox
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How can you prove that the normal equations: $(X^TX)\beta = X^TY$ have one or more solutions without the assumption that X is invertableinvertible?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

How can you prove that the normal equations: $(X^TX)\beta = X^TY$ have one or more solutions without the assumption that X is invertable?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

How can you prove that the normal equations: $(X^TX)\beta = X^TY$ have one or more solutions without the assumption that X is invertible?

My only guess is that it has something to do with generalized inverse, but I am totally lost.

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ryati
ryati
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Question about a normal equation proof

How can you prove that the normal equations: $(X^TX)\beta = X^TY$ have one or more solutions without the assumption that X is invertable?

My only guess is that it has something to do with generalized inverse, but I am totally lost.