Timeline for Evaluate enhancement using hyphotesis tests
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Jan 27 at 0:04 | history | bounty ended | CommunityBot | ||
| S Jan 27 at 0:04 | history | notice removed | CommunityBot | ||
| Jan 25 at 11:08 | vote | accept | Lin | ||
| Jan 25 at 4:14 | comment | added | usεr11852 | Also to stay something else, you probably want some sort of multiple testing correction (see the concept of Bonferroni correction for example). | |
| Jan 24 at 7:20 | answer | added | DrJerryTAO | timeline score: 2 | |
| Jan 21 at 14:33 | comment | added | whuber♦ | That ratio makes no sense. Your percentages, however, correspond to differences in the thousands, each of which is ten or more times any standard error: that is so large that no testing is needed. | |
| Jan 21 at 1:26 | comment | added | Lin | Some are bigger the last are smaller. We can compute a ratio $\frac{SE_i}{SE_{tot} - SE_i} \approx [ 0.79, 0.60, 0.70, 0.92, 1.05 ]$. | |
| Jan 20 at 17:58 | comment | added | whuber♦ | Good. And how do the differences in the total returns compare to those SEs? | |
| Jan 20 at 0:59 | comment | added | Lin | For each $i$-percentage we have the given the approximate $i$-th SE: ${SE}_i = \sqrt{(p * (1-p)) / (1/n)} \approx [94, 80, 88, 102, 109]$. SE total, computed with $SE_{tot} = \sqrt{\sum{SE_i^2}} \approx 214$. Computing the differences $SE_{tot} - SE_i \approx [119, 134, 126,111, 104]$, | |
| Jan 18 at 22:24 | comment | added | whuber♦ | You're working too hard. What, approximately, are the standard errors of the total return in each experiment? How do the differences in total returns compare to those standard errors? | |
| S Jan 18 at 22:08 | history | bounty started | Lin | ||
| S Jan 18 at 22:08 | history | notice added | Lin | Draw attention | |
| Jan 15 at 11:22 | history | edited | Lin | CC BY-SA 4.0 |
deleted 4 characters in body
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| Jan 15 at 11:17 | history | asked | Lin | CC BY-SA 4.0 |