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fairidox
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Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect there may be a way since the different events (for each $j$) are clearly not independent, I'm not aware of any way to exploit this dependence. Also, it would be nice to remove the restriction that $c$ is greater than the mean.

edit: The restriction on $c$ being greater than the mean can be removed if we use Markov's Inequality as follows:

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n \frac{\frac{1}{j}\mathbb{E}[X]}{c} \\ & = \frac{\mathbb{E}[X]H_n}{c} \end{align} Which is more general, but much worse than the above bound, although it's clear that $\mathcal{T}$ must diverge whenever $c \leq \mathbb{E}[X]$.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect there may be a way since the different events (for each $j$) are clearly not independent, I'm not aware of any way to exploit this dependence. Also, it would be nice to remove the restriction that $c$ is greater than the mean.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect there may be a way since the different events (for each $j$) are clearly not independent, I'm not aware of any way to exploit this dependence. Also, it would be nice to remove the restriction that $c$ is greater than the mean.

edit: The restriction on $c$ being greater than the mean can be removed if we use Markov's Inequality as follows:

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n \frac{\frac{1}{j}\mathbb{E}[X]}{c} \\ & = \frac{\mathbb{E}[X]H_n}{c} \end{align} Which is more general, but much worse than the above bound, although it's clear that $\mathcal{T}$ must diverge whenever $c \leq \mathbb{E}[X]$.

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fairidox
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Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect sothere may be a way since the different events (for each $j$) are clearly not independent, I'm actually looking for an expectation innot aware of any way to exploit this dependence. Also, it would be nice to remove the end and Hoeffding'srestriction that $c$ is more generalgreater than is neededthe mean.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect so since I'm actually looking for an expectation in the end and Hoeffding's is more general than is needed.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect there may be a way since the different events (for each $j$) are clearly not independent, I'm not aware of any way to exploit this dependence. Also, it would be nice to remove the restriction that $c$ is greater than the mean.

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fairidox
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Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n j \times \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$$$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n j \times e^{-2ja^2} \\ & = \frac{e^{-2 a^2 n} \left(e^{2 a^2 (n+1)}-e^{2 a^2} (n+1)+n\right)}{\left(e^{2 a^2}-1\right)^2} \end{align}\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect so since I'm actually looking for an expectation in the end and Hoeffding's is more general than is needed.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n j \times \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n j \times e^{-2ja^2} \\ & = \frac{e^{-2 a^2 n} \left(e^{2 a^2 (n+1)}-e^{2 a^2} (n+1)+n\right)}{\left(e^{2 a^2}-1\right)^2} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect so since I'm actually looking for an expectation in the end and Hoeffding's is more general than is needed.

Given a sequence of i.i.d. random variables, say, $X_i \in [0,1]$ for $i = 1,2,...,n$, I'm trying to bound the expected number of times the empirical mean $\frac{1}{n}\sum_{i=1}^n X_i$ will exceed a value, $c \geq 0$, as we continue to draw samples, that is: $$ \mathcal{T} \overset{def}{=} \sum_{j=1}^n \mathbb{P} \left(\left\{ \frac{1}{j}\sum_{i=1}^j X_i \geq c\right\}\right) $$

If we assume that $c = a + \mathbb{E}[X]$ for some $a > 0$, we can use Hoeffding's inequality to arrive at

\begin{align} \mathcal{T} & \leq \sum_{j=1}^n e^{-2ja^2} \\ & = \frac{1 - e^{-2 a^2 n}}{e^{2 a^2}-1} \end{align}

Which looks nice (maybe) but is actually quite a loose bound, are there any better ways of bounding this value? I expect so since I'm actually looking for an expectation in the end and Hoeffding's is more general than is needed.

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