Timeline for Exercise of Hypothesis Testing
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Aug 10, 2013 at 14:59 | answer | added | Justin Bozonier | timeline score: 1 | |
Aug 10, 2013 at 13:48 | comment | added | ABC | @JustinBozonier A two sided test, statistic $z=2.42$. $p-$value$=2*0,0078$. Can you please explain why did we multiply $2$ instead of dividing? | |
Aug 10, 2013 at 13:41 | comment | added | Justin Bozonier | For a two sided test I believe you just use alpha/2 as alpha. | |
Aug 10, 2013 at 13:28 | comment | added | ABC | @COOLSerdash Can you please give me reference on one-sided test and two-sided test. My main problem is to compute the value based on one-sided test and two-sided test. | |
S Aug 10, 2013 at 12:59 | history | suggested | QuantIbex | CC BY-SA 3.0 |
Improved formatting and wording
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Aug 10, 2013 at 12:57 | comment | added | COOLSerdash | If the population standard deviation is known, then you can use a $z$-test. As far as I understand your setup, you assume to know the population standard deviation to be $500$. If you estimate the population standard deviation by the sample standard deviation, a $t$-test is normally used. In large samples, the difference between the $z$-test and $t$-test are negligible. The critical $t$ value on the linked page is the $0.95$ quantile of the $t$-distribution with $34$ degrees of freedom. The $0.95$ quantile of the standard normal is $1.644$, not $1.96$ (because you have a one-sided test). | |
Aug 10, 2013 at 12:55 | comment | added | QuantIbex | The test is one-sided, you need to check the rejection region of your approach. | |
Aug 10, 2013 at 12:48 | review | Suggested edits | |||
S Aug 10, 2013 at 12:59 | |||||
Aug 10, 2013 at 12:39 | history | asked | ABC | CC BY-SA 3.0 |