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Jun 7, 2016 at 16:49 comment added Alecos Papadopoulos @MrYouMath $I$ is the identity matrix and so it is diagonal. This is the "homoskedastic and uncorrelated errors" assumption. Normality is not assumed.
Jun 7, 2016 at 16:26 comment added MrYouMath Could you explain why $E(UU'\mid Z) = \sigma^2I$ does that imply that the variance of each error term is equal to $\sigma^2$? I rather thought that it should be a diagnoal matrix. Which assumption is this (uncorrelated errors + Normal distribution?)?
Oct 16, 2013 at 11:45 history answered Alecos Papadopoulos CC BY-SA 3.0