Timeline for Comparing means with unequal variance and very different sample sizes
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 3, 2013 at 23:48 | history | edited | Glen_b | CC BY-SA 3.0 |
added 303 characters in body
|
| Nov 3, 2013 at 23:46 | comment | added | Glen_b | No, I don't think so. I have made an edit to make the reduced relevance of my answer clear though; it's now of minor general interest for a related situation, rather than a direct answer to your present question (so if you do accept an answer, you should probably not choose mine.) | |
| Nov 3, 2013 at 23:45 | comment | added | LF12 | Should I repost? | |
| Nov 3, 2013 at 23:28 | comment | added | Glen_b | My comments no longer apply to the new data. | |
| Nov 3, 2013 at 22:30 | comment | added | LF12 | Forgot I was only analyzing in a given time range, sorry about this. | |
| Nov 3, 2013 at 21:54 | comment | added | Glen_b | Why are the data now quite different to the data my answer related to? | |
| Nov 3, 2013 at 16:20 | comment | added | LF12 | Thanks, I added in the coef. of variation, and the data changed slightly but they are not equal. The distribution of the data is pretty close to log normal so I am wondering the best way to test these means against each other. I feel like the sample size will limit me, but can I get around this? | |
| Nov 3, 2013 at 9:20 | history | answered | Glen_b | CC BY-SA 3.0 |