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Dec 10, 2013 at 10:15 vote accept t t
Nov 21, 2013 at 0:35 comment added Peter Flom No it doesn't assume $\mu = 1.35$, it assumes it is either <= 1.35 or >= 1.35. An H0 that $\mu = 1.35$ could be rejected 100% of the time with no error. $PR(\mu = 1.35) = 0$
Nov 21, 2013 at 0:04 comment added t t Are you talking about H1: μ > 1.35 then P(Z ≥ z) and H1: μ < 1.35 means p-value is P(Z ≤ z)? but this assumes H0 = 1.35. The question I'm asking has H0 with inequality too! Are you saying it doesn't matter? (Both H0 and H1 have inequalities in my question!)
Nov 20, 2013 at 23:55 comment added Peter Flom You already wrote the solution to that in your problem, in the second box
Nov 20, 2013 at 23:19 comment added t t Yes, I agree p-value is not z or 2*z. Just a typo. Please see my edit above. Now, how to compute p-value when H0 is not a fixed constant but a range of values? (inequality sign)
Nov 20, 2013 at 12:42 history answered Peter Flom CC BY-SA 3.0