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Jan 30, 2015 at 11:15 history edited Peter Flom CC BY-SA 3.0
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Jan 20, 2014 at 23:32 comment added jpmuc Great point,+1. Just consider the expression $(x-a)^{2}+(x-b)^{2}$ and calculate its minimum. It is the midpoint between a and b. This is contrast with the $L_{1}$ error function, a.k.a. robust regression
Jan 20, 2014 at 23:30 comment added Peter Flom Yes, I meant the mean of Y. That is what OLS regression does.
Jan 20, 2014 at 23:08 comment added Manuel Or did you meant, the mean of $Y$ ?
Jan 20, 2014 at 23:05 comment added Manuel what do you mean with not wanting to estimate the mean? I am considering $\beta$ as a fixed parameter in a frequentist approach, if that what you are talking about.
Jan 20, 2014 at 22:58 history answered Peter Flom CC BY-SA 3.0