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Feb 7, 2014 at 14:36 history edited Vyga CC BY-SA 3.0
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Feb 7, 2014 at 14:12 comment added Scortchi Continuing this approach, $\operatorname{E} (R) = \sigma \int_{-\infty}^{\infty} 1-(1-\Phi(x))^n -\Phi(x)^n\, \mathrm{d} x = \sigma d_2(n)$, where $R$ is the range & $\Phi(\cdot)$ the standard normal cumulative distribution function. You can find tabulated values of $d_2$ for small $n$ in the statistical process control literature, numerically evaluate the integral, or simulate for your $n$.
Feb 7, 2014 at 13:19 history edited Scortchi CC BY-SA 3.0
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Feb 7, 2014 at 13:17 history edited Vyga CC BY-SA 3.0
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Feb 7, 2014 at 12:17 review First posts
Feb 7, 2014 at 12:49
Feb 7, 2014 at 11:59 history answered Vyga CC BY-SA 3.0