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Probability of ($x\le$X \le 2Y$)

$X$ and $Y$ are independent and their probability density functions are $$f_X(t)=f_Y(t)=\left\{\begin{array}{l} e^{-t},\:\text{if $t \geq 0$;} \\ 0,\:\text{otherwise.}\end{array}\right.$$$$f_X(t)=f_Y(t)=\left\{\begin{array}{ll} e^{-t},&\text{if $t \geq 0$;} \\ 0,&\text{otherwise.}\end{array}\right.$$

$P(X \leq 2Y)$=? (The probability of $X \leq 2Y$)

Probability of ($x\le 2Y$)

$X$ and $Y$ are independent and their probability density functions are $$f_X(t)=f_Y(t)=\left\{\begin{array}{l} e^{-t},\:\text{if $t \geq 0$;} \\ 0,\:\text{otherwise.}\end{array}\right.$$

$P(X \leq 2Y)$=? (The probability of $X \leq 2Y$)

Probability of $X \le 2Y$

$X$ and $Y$ are independent and their probability density functions are $$f_X(t)=f_Y(t)=\left\{\begin{array}{ll} e^{-t},&\text{if $t \geq 0$;} \\ 0,&\text{otherwise.}\end{array}\right.$$

$P(X \leq 2Y)$=? (The probability of $X \leq 2Y$)

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Probability of (x=<2Y$x\le 2Y$)

X$X$ and Y$Y$ are independent and their probability density functions are

fX(t)=fY(t)=e^(-t) for t>=0. 0, otherwise. $$f_X(t)=f_Y(t)=\left\{\begin{array}{l} e^{-t},\:\text{if $t \geq 0$;} \\ 0,\:\text{otherwise.}\end{array}\right.$$

P(X=<2Y)$P(X \leq 2Y)$=? (The probability of X=<2Y$X \leq 2Y$)

Probability of (x=<2Y)

X and Y are independent and their probability density functions are

fX(t)=fY(t)=e^(-t) for t>=0. 0, otherwise.

P(X=<2Y)=? (The probability of X=<2Y)

Probability of ($x\le 2Y$)

$X$ and $Y$ are independent and their probability density functions are $$f_X(t)=f_Y(t)=\left\{\begin{array}{l} e^{-t},\:\text{if $t \geq 0$;} \\ 0,\:\text{otherwise.}\end{array}\right.$$

$P(X \leq 2Y)$=? (The probability of $X \leq 2Y$)

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