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Is there any way to run an OLS difference in differences model when the dependent variable (investment) has lots of observations which are truly zero?

I don´t know how to add clarifications. My problem is indeed the normality assumption. I am using firm level panel data. Many firms (around 60%) do not invest each year. That`s why I have so many zeroes.

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  • $\begingroup$ What sorts of problems are you having when you do this? $\endgroup$
    – dimitriy
    Commented Aug 31, 2012 at 21:21
  • $\begingroup$ @Michael I've merged your previous account with this one. $\endgroup$
    – user88
    Commented Sep 1, 2012 at 15:29

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I would try fitting a panel count data model (probably a negative binomial rather than a poisson) with a DD specification (treatment, post-treatment, and their interaction dummies). See if that produces sensible results. Compare to your fixed effects DD and the poisson DD. This is probably OK if zero is not special.

But you also have to think hard about the economics of the corner solution and how that interacts with your treatment. There is whole class of two part aka hurdle aka selection models where you treat the extensive and intensive margins separately (participation vs levels of outcome). The DGP for y=0 and y>0 may be very different. This is the second approach, harder to fit into a DD frame, but more serious.

Cameron and Trivedi's microeconometrics books are a good applied reference.

Answer to Question from Below: I could not get the linking to work in the comment, so I added it to my answer.

Like OLS, NB is a model for $E[y|x]$, just with a functional form of $\exp{x'\beta}.$ I believe it should be OK. Here's one published (gated) example, which I have not personally read. Wooldridge and Imbens also mention this approach briefly in their NBER metrics summer course notes from 2007. You might also code up a simple simulation to convince yourself that this works.

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  • $\begingroup$ I have thought of fitting a panel count data model with a DD specification but I wonder if it is feasible. In a basic DD setup you basically compare two means. I do not know how this works in a negative binominal model. Expecially I am unsure because I could not find any reference paper using a count data model with a DD specification. any hint on that? $\endgroup$
    – Michael
    Commented Sep 3, 2012 at 17:47
  • $\begingroup$ To be precise, you are comparing 4 means. See my answer above. $\endgroup$
    – dimitriy
    Commented Sep 4, 2012 at 21:10
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I think there are difficulties because if the dependent variable has that property you can't expect the model residuals to be normally distributed. It might be important to first understand why you have so many zeros.

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