1
$\begingroup$

I am studying experiment design, and I am trying to understand why certain designs have the Expected Mean Squares that they do. Today, I want to ask about a particular design: the 2-Factor Repeated Measures Design.

(1) I like to depict the 2-Factor RM design with the following example data structure:

  • U = Experiment Units
  • F = Factor F with 2 Levels
  • G = Factor G with 2 Levels
  • Replicates = 1 per (U x F x G) combination

enter image description here

(2) I imagine the randomization scheme to be a two-step randomization, as a 2-Factor CRD inside each Unit. I depict the randomization scheme as a "flow chart" diagram:

enter image description here

(3) I believe the model equation is (via a textbook):

  • M = O + U + F + [U:F] + G + [U:G] + F:G + [U:F:G]

(4) And I believe the Expected Mean Squares is (via a textbook):

enter image description here

(5) QUESTION

  • It's obvious what the Expected Mean Squares [E(MS)] are showing, namely that the treatment factor terms F, G, and F:G in the model have E(MS) that are the E(MS) of their corresponding U:F, U:G, and U:F:G terms, plus an additional value specific to themselves. The result is that for an ANOVA analysis, the correct F-test ratios are F/U:F, G/U:G, and F:G/U:F:G.
  • My question is how can I calculate these Expected Mean Squares? (A) The structure of the data set is clearly that F, G, and U are all crossed with each other. (B) The only difference between this 2-Factor Rm Design and a 3-Factor CRD Design seems to be the randomization scheme, since this 2-Factor RM Design is randomized like a 2-Factor CRD within the Units. (C) The model equation is even identical to a 3-Factor CRD Design with No Replicates.
  • So I am a bit stuck, because I can't figure out how I would calculate the correct E(MS) for this 2-Factor RM Design. Any advice or suggestions are welcome. Thank you! Cheers, Chris
$\endgroup$

1 Answer 1

0
$\begingroup$

Found out that the textbook I referenced about repeated measures designs typically models the Units as random effects. This is probably why there is a difference between 3-Factor CRD and 2-Factor RM in their Expected Mean Squares.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.