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Qwerty
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$\lim_{x\to\infty}{1-\Phi(x)\over \phi(x)/x}=1$

I have the following to prove :

Let $\phi$ and $\Phi$ denote the standard normal density and distribution functions respesctively. Prove that $$\lim_{x\to\infty}{1-\Phi(x)\over \phi(x)/x}=1$$

I am not being able to start. $\Phi$ is basically $\int \phi(x)dx$. How to calculate the limit?

Qwerty
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