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corrected English in title, formatting, relevant tag
Glen_b
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Intuitive explanation for dividing by $n-1$ when calculating sd?

I was asked today in class why you divide the sum of square error by $n-1$ instead of with $n$, when calculating the standard deviation.

I said I am not going to answer it in class (since I didn't wanna go into unbiased estimators), but later I wondered - is there an intuitive explanation for this?!

Tal Galili
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