From your first two lines, your prior implies $E[Y] = N\frac{a}{b}$
So with $E(\lambda\mid Y)=\frac{Y+a}{N+b}$, you have $E\left[E(\lambda\mid Y)\right] =E\left[\frac{Y+a}{N+b}\right]=\frac{E\left[Y\right] +a}{N+b}= \frac{N\frac{a}{b}+a}{N+b} = \frac{a}{b}$
which is what you might have thought from your first line and the law of total expectation