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A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

 

a. What formula to use.
b. Plug all values in.

I think I should use a $t$-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$, so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$. What is the $\mu_0$ value? Am I right?

A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

 

a. What formula to use.
b. Plug all values in.

I think I should use a $t$-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$, so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$. What is the $\mu_0$ value? Am I right?

A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

a. What formula to use.
b. Plug all values in.

I think I should use a $t$-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$, so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$. What is the $\mu_0$ value? Am I right?

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gung - Reinstate Monica
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A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

a. What formula to use.
b. Plug all values in.

I think I should use a t$t$-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$ so, so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$. What is the $\mu_0$ value? Am I right?

A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

a. What formula to use.
b. Plug all values in.

I think I should use a t-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$ so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$ What is the $\mu_0$ value? Am I right?

A psychologist is collecting data on the time it takes to learn a certain task. For $55$ randomly selected adult subjects, the sample mean is $10.5$ minutes and sample standard deviation is $3.25$ minutes. Construct a $99\%$ confidence interval for the mean time required by all adults to learn the task.

a. What formula to use.
b. Plug all values in.

I think I should use a $t$-test formula which would be $(\bar x- \mu_0 )/(s/\sqrt n)$, so plugging in the values would be $(10.5-?)/(3.25/\sqrt{55})$. What is the $\mu_0$ value? Am I right?

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whuber
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Deciding What is the formula to use and plug in valuesfor a normal-theory confidence interval of the mean?

added tag; formatted; light editing
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gung - Reinstate Monica
  • 147.5k
  • 89
  • 406
  • 717
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