No. In the coordinate systems you've chosen, they are not linearly separable. The classes of data must be separable by a hyperplane, that is, a boundary that takes the form of $w_1x_1 + w_2x_2 + ... + w_px_p = C$. If you can find a coordinate system where this is true, and transformthen it to thiswill be linearly separable in the new coordinate system, only then will it be considered linearly separable but not necessarily in the old.