No. In the coordinate systems you've chosen, they are not linearly separable. The classes of data must be separable by a hyperplane, that is, a boundary that takes the form of $w_1x_1 + w_2x_2 + ... + w_px_p = C$. If you can find a coordinate system where this is true, then it will be linearly separable in the new coordinate system but not necessarily in the old.
matt
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