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I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

 

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

 

The two-tailed p-value for tdata = 0.6594 is :

 

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

 

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

 

The two-tailed p-value for tdata = 0.6594 is :

 

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

Added self-study tag; formatted quote from book and code.
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I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595) 2 x p (t > 0.6595). So, I don't know what numbers the variable pp and tt are equivalent to in order to give me that results. Also, I don't understand ">"">" being there and how is that calculated. Does it make sense?

I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

added 2 characters in body; edited title
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Nick Cox
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help me understand how How a two-tailed p-value is calculated for a two-sample t-test

I'm reading discovering knowledge in DataDiscovering Knowledge in Data by Daniel T. LaRoseLarose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. doesDoes it make sense?

help me understand how a two-tailed p-value is calculated for a two-sample t-test

I'm reading discovering knowledge in Data by Daniel T. LaRose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. does it make sense?

How a two-tailed p-value is calculated for a two-sample t-test

I'm reading Discovering Knowledge in Data by Daniel T. Larose. In the two-sample t-test for difference in means section, there is the following example:

tdata = x-bar(1) - (xbar2)/ sqrt(s^2(1)/n(1)+ s^2(2)/(n2) =

1.5714 - 1.5361 / 1.3126^2 + 1.3251^2 = 0.6595

The two-tailed p-value for tdata = 0.6594 is :

p-value = 2 x p(t> 0.6595) = 0.5098

My problem is that there is no reference or explanation in the book about how the result 0.5098 came to be. For example, how do we get 0.5098 from 2 x p (t > 0.6595). So, I don't know what numbers the variable p and t are equivalent to in order to give me that results. Also, I don't understand ">" being there and how is that calculated. Does it make sense?

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KetDog
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