Timeline for Definition of (contiuous-time) Markov chain transition rate
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Apr 6, 2018 at 9:11 | history | edited | Benoit Sanchez | CC BY-SA 3.0 |
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| Apr 2, 2018 at 10:51 | vote | accept | Physkid | ||
| Apr 2, 2018 at 9:59 | answer | added | Winkelried | timeline score: 2 | |
| Apr 2, 2018 at 8:41 | history | edited | Physkid | CC BY-SA 3.0 |
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| Apr 2, 2018 at 8:29 | history | edited | Physkid | CC BY-SA 3.0 |
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| Apr 2, 2018 at 8:28 | comment | added | Physkid | If that is not a probability, then, I will struggle to know. The author has not defined what that means. | |
| Apr 2, 2018 at 8:25 | review | Close votes | |||
| Apr 7, 2018 at 11:44 | |||||
| Apr 2, 2018 at 8:11 | comment | added | Xi'an | What is $q(i,j)$? Not a probability, obviously. And please add the reference to the quote you reposted. | |
| Apr 2, 2018 at 8:09 | comment | added | Physkid | @Xi'an Edited. Hope that helps | |
| Apr 2, 2018 at 8:08 | history | edited | Physkid | CC BY-SA 3.0 |
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| Apr 2, 2018 at 8:05 | comment | added | Xi'an | Unclear question: what is the role of $t$? And, given the definition of $\lambda_i$, which is the probability of not staying in $i$, i.e., $1-q(i,i)$, it is not a rate. | |
| Apr 2, 2018 at 6:33 | history | edited | Physkid | CC BY-SA 3.0 |
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| Apr 2, 2018 at 6:16 | history | asked | Physkid | CC BY-SA 3.0 |