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Jan 10, 2019 at 12:54 comment added Tommaso Bendinelli Also do we know the distribution $F(\theta_{z_i})$?
Jan 10, 2019 at 12:49 comment added Tommaso Bendinelli I don't get both your point, (i) where have you seen $X|Z = Z|X$, (ii) What you "by is indexed".
Jan 10, 2019 at 12:42 comment added Tommaso Bendinelli If $ X|Z=k\sim p(x|\theta_k)$ and $X|Z\sim p(x|\theta_Z)$ are identical, because both represent the random varialbe $X|Z$ why in one case $\theta$ is $\theta_k$ and in the other $\theta_z$ ?
Jan 10, 2019 at 12:35 history edited Xi'an CC BY-SA 4.0
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Jan 10, 2019 at 12:23 comment added Tommaso Bendinelli Thank you! And what is the difference between $\boldsymbol\theta_k$ and $\boldsymbol\theta_{z_i}$? And what is meant by "We can write > $p(x_i|\boldsymbol\theta_k)$ as $\boldsymbol{x}_i \sim F(\boldsymbol\theta_{z_i})$ where F is the observation distribution"?
Jan 10, 2019 at 12:19 history answered Xi'an CC BY-SA 4.0