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Dec 8, 2021 at 7:43 comment added Xi'an See also the discussion on this question: stats.stackexchange.com/q/507236/7224
Dec 8, 2021 at 7:20 comment added Xi'an $Y|X$ as such does not have a meaning. $Y$ is a random variable and $(X,Y)$ is a pair of random variables.
Dec 7, 2021 at 22:51 comment added gnikol So $Y|X=x$ is defined as a conditional probability distribution conditional on the realization of the random variable $X$. Also, as Xi'an correctly points out $E[Y|X] $ is also a random variable and $E[Y|X=x] $ is a function of $X$. My question is how $Y|X$ is defined?
Dec 7, 2021 at 21:17 comment added Guilherme Marthe This means that the $Y$ random variable, conditioned on the realization $x$ of the random variable $X$ is normally distributed with mean $5x$ and standard deviation $\sigma$.
Dec 7, 2021 at 21:00 comment added gnikol If neither are defined as such then how can we say that $Y|X=x\sim \mathcal{N}(5x,\,\sigma^{2})\,$. Am I missing something?
Dec 7, 2021 at 20:59 history edited gnikol CC BY-SA 4.0
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Dec 7, 2021 at 20:10 comment added Xi'an Neither are defined as such. When writing $\mathbb E[Y|X]$ this is understood as a random variable that is a (deterministic) transform of the random variable $X$. When writing $\mathbb E[Y|X=x]$ this is understood as the realisation of the above rv when the realisation of $X$ is $x$.
Dec 7, 2021 at 20:06 history asked gnikol CC BY-SA 4.0