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Prove that E[x^n] >= (EX)^n for n = 2k$E[x^n] \geq (Ex)^n$ for $n = 2k$
E[x^n] >= (EX)^n for n = 2k
I only have the formula of E(x) but I don't know how to prove it.
Prove that E[x^n] >= (EX)^n for n = 2k
Prove that $E[x^n] \geq (Ex)^n$ for $n = 2k$
